asked 45.2k views
10 votes
if f(x)=ax^3+bx^2+cx+d find f(1), f(2), f(3), f(4), f(5), f(6) and show that the third differences of these values are constant.

asked
User Mpiktas
by
7.4k points

1 Answer

7 votes

Answer:

third differences are all 6a

Explanation:

Substituting for x, we find the sequence values to be ...

(a+b+c+d), (8a+4b+2c+d), (27a+9b+3c+d), (64a+16b+4c+d), (125a+25b+5c+d),

(216a+36b+6c+d)

Then first differences are ...

(7a+3b+c), (19a+5b+c), (37a+7b+c), (61a+9b+c), (91a+11b+c)

Second differences are ...

(12a+2b), (18a+2b), (24a+2b), (30a+2b)

And the third differences are ...

(6a), (6a), (6a) . . . . . constant

_____

Additional comment

These results can help you write a polynomial relation up to 3rd degree for a sequence that has constant differences at any level up to 3rd differences.

Of course, we find the differences by subtracting each term from the one following.

answered
User Supun Induwara
by
8.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.