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Solve (y-4)^2+63=0 where y is a real number.

Solve (y-4)^2+63=0 where y is a real number.
asked 222k views
3 votes
Solve (y-4)^2+63=0 where y is a real number.

asked
User Scord
by
8.4k points

1 Answer

5 votes

Answer:


y = 4 + 3 √(7) i

Explanation:


(y-4)^2+63=0 \\ \\ (y-4)^2 = - 63 \\ \\ (y-4)= √( - 63) \\ \\ y - 4 = 3 √(7) i \\ \\ y = 4 + 3 √(7) i

answered
User Nickyfot
by
7.8k points
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