How many atoms are in a sample of uranium with a mass of 789 g.

Question

asked Nov 6, 2021 115k views

1 Answer

Arijit · Answer 1 · 2021-11-11T16:08:44+0000

Number of atoms : 1.996 x 10²⁴

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

mol of Uranium with mass=789 g (Ar U=238,02891 u) :

$\tt mol=(mass)/(Ar)\\\\mol=(789)/(238,02891 u)\\\\mol=3.315$

Number of atoms :

$\tt N=3.315* 6.02* 10^(23)\\\\N=1.996* 10^(24)~atoms$