Question

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Find the minimum value of the function f(x) = x2 + 12x + 31.5 to the
nearest hundredth.

Answer 1

x = -6.00 (rounded to nearest hundredth)

Explanation:

• for a quadratic equation,
  `h(x)=ax^2+bx+c`
• we have
  `f(x)=x^2+12x+31.5`
• a = 1
• b = 12
• to find minimum use equation
  `x=(-b)/(2a)`

• 
  `x=(-b)/(2a)\\x=(-(12))/(2(1))\\x=(-12)/(2)=-6`

Answer 2

The answer is pie

Explanation:

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