Question

The average speed of an oxygen molecule is 6.14 x 104 cm/sec at a certain temperature. What is the average speed of a CO2 molecule at the same temperature? (molar mass O2 = 31.9988; CO2 = 44.0098)

Answer 1

the average speed of
`V_(av) CO_2` is 5.24 × 104 cm/s

Step-by-step explanation:

The computation of the average speed of a
`CO_2` is as follows:

`√(average) = \sqrt{(8 RT)/(\pi M) }`

where,

M = Molar mass

`V_(av) = (√(1))/(M)`

Given that

`V_(av) \ of\ oxygen= 6.14 * 10^4 cm/s`

The molar mass of oxygen i.e. (MO_2) = 31.9988 g/mol

And, the molar mass of CO_2 is 44.0098 g/mol

Now

`(V_(av) CO_2)/(V_(av) O_2) = \frac{\sqrt{M_(O2) }}{M_(CO2)}`

Now place these values to the above formula

`(V_(av)CO_2)/(6.14* 104 cm/s) = (√(31.9988) )/(44.0098)`

So,

V_av CO_2 is 5.24 × 104 cm/s

hence, the average speed of
`V_(av) CO_2` is 5.24 × 104 cm/s