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2 votes
Solve and state any extraneous solutions

Solve and state any extraneous solutions-example-1
asked
User Raxit
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8.2k points

1 Answer

3 votes


(3x)/(x - 1) + 2 = (3)/(x - 1)


(3x)/(x - 1) + (2(x - 1) )/( x - 1) = (3)/(x - 1)


(3x)/(x - 1) + (2x - 2)/( x - 1) = (3)/(x - 1)


(3x + 2x - 2)/( x - 1) = (3)/(x - 1)


3x + 2x - 2 = 3


5x - 2 = 3


5x = 3 + 2


5x = 5


x = (5)/(5)


x = 1

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