Question

HELP PLEASE

The sum of three numbers is 19. The third number is eleven less than five times the second number. If the first number is quadruple the amount of the second number, what is the value of the third number? (may I have the equation please)

Answer 1

third number = 4,

equation of y, y = 5x - 11

equation of n, n = 4x

equation of x, n + x + y =19

Explanation:

so lets write evertything as a n equation. n + x + y =19. N is the first number, x is the second number, and y is the third number. We will write the equation for y as follows 5x - 11. N will be four times the second number, so 4x. If substitute the values for out equation for x we will find what x equals to. So (4x) + x + (5x - 11) = 19

10x = 30

x = 3.

Then you substiute the answer for x in the equation for y. This will get you 5(3) - 11

15 - 11

4 = third number