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Triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?

Triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?
asked 137k views
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triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?

asked
User Elmex
by
7.9k points

1 Answer

0 votes

Explanation:

midpoint of AC=(x¹+x²/2,y¹+y²/2)

=(-12+6/2,-8+14/2)

=(-6/2, 6/2)

=(-3,3)

answered
User Amir T
by
8.4k points
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