Answer:
So, at the depth of 24 cm below the surface of the glycerine the pressure is 2970 Pa. Hence, this is the required solution.
Step-by-step explanation:
Given that, 
 
Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure. 
 
The density of glycerine, 
 
We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by : 
 
 
 
 
 
 
 
h = 0.24 meters 
 
or 
 
h = 24 cm