\sqrt[3]{x}=\sqrt[5]{32} why can't i just cube both sides, therefore kick the x out of the cubic root, and then i would have x = √(32) \\then \\x = √(16 * 2)\\x = 4√(2)

Question

`\sqrt[3]{x}=\sqrt[5]{32}`

why can't i just cube both sides, therefore kick the x out of the cubic root, and then i would have

`x = √(32) \\then \\x = √(16 * 2)\\x = 4√(2)`

Answer 1

`x = 8`

Explanation:

`{x}^{ (1)/(3) } = {32}^{ (1)/(5) }`

`{( {x}^{ (1)/(3) } )}^(3) = {( {32}^{ (1)/(5) } )}^(3)`

`{x}^(1) = \sqrt[5]{ {32}^(3) }`

`x = \sqrt[5]{32768}`

`x = 8`