Question

A vector has a horizontal component of 14 and a vertical component of 36. Find the direction angle and the magnitude. Direction angle?

Answer 1

The direction angle is 68.73 degrees and its magnitude is 38.62.

Explanation:

Given that,

The horizontal component of a vector = 14

The vertical component of a vector = 36

Let the magnitude of a vector is v. So,

`v=√(14^2+36^2) \\\\=38.62`

For direction,

`\tena\theta=(y)/(x)\\\\=(36)/(14)\\\\\theta=\tan^(-1)(2.57)\\\\=68.73^(\circ)`

So, the direction angle is 68.73 degrees and its magnitude is 38.62.