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How many zeros does the function have? f(x) = x^3 – 5x^2 – 8x + 48

How many zeros does the function have? f(x) = x^3 – 5x^2 – 8x + 48
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How many zeros does the function have?
f(x) = x^3 – 5x^2 – 8x + 48

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User Zelazowy
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1 Answer

7 votes

Answer:

x^(3)+5x^(2)-8x-48=0

answered
User Matthias Schobner
by
7.1k points
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