Question

What is the factorization of the polynomial below?
9x2 - 16

Answer 1

Answer:-

`\bigcirc`(9x+4)(x-4)

`\bigcirc`(9x-4)(x-4)

`\odot`(3x+4)(3x-4)

`\bigcirc`(3x-4)(3x-4)

_____________________

Calculations:-

Let's Factorise:-

`{:}\leadsto`
`\sf 9x^2-16`

• Let's use algebraic identity for factorisation

`{\boxed{\sf (a+b)(a-b)=(a)^2-(b)^2}}`

• Here see 16 is the square of 4 and 9x^2 is the square of 3x

`{:}\leadsto`
`\sf 3x^2-4^2`

• Now According to identity

`{:}\leadsto`
`\sf (3x+4)(3x-4)`

Hence the correct option is option C.

Answer 2

use (a-b) (a+b )

(3x+4) (3x- 4)