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Explain how the parts of the balanced hanger compare to the parts of the equation. 7 = 2x + 3

Explain how the parts of the balanced hanger compare to the parts of the equation. 7 = 2x + 3
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Explain how the parts of the balanced hanger compare to the parts of the equation.

7 = 2x + 3

Explain how the parts of the balanced hanger compare to the parts of the equation-example-1
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User FluffyJack
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1 Answer

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The mass of the red circle is heavy
So x is 2 so each circle is 2 when the squares are one . Is this what ur asking?
answered
User Tcooc
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8.0k points
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