Question

How many moles of oxygen are required for the combustion of 35.5 g of Magnesium Mg+O2-->MgO Please balance

Answer 1

0.74 moles of oxygen are required for combustion

Step-by-step explanation:

Given data:

Number of moles of oxygen required = ?

Mass of Mg = 35.5 g

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 35.5 g/ 24 g/mol

Number of moles = 1.48 mol

Now we will compare the moles of Mg with oxygen.

Mg : O₂

2 : 1

1.48 : 1/2×1.48 = 0.74 mol

0.74 moles of oxygen are required for combustion.