Question

An airplane accelerates with a constant rate of 3.0 m/s2

starting at a velocity of 21 m/s. If the final velocity is 60 m/s,

what is the displacement during this period?

Answer 1

526.5m

Step-by-step explanation:

Given parameters:

Acceleration = 3m/s²

Initial velocity = 21m/s

Final velocity = 60m/s

Unknown:

Displacement = ?

Solution:

To solve this problem, we apply the right motion equation which is shown below;

V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the displacement

Insert the parameters and solve;

60² = 21² + 2(3)S

3600 = 441 + 6S

3600 - 441 = 6S

3159 = 6S

S = 526.5m