Question

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Answer 1

The concentration of [OH-] -hydroxide ion : 1.2 x 10⁺⁴ M

Further explanation

H₂O ionization reaction

2 H₂O ⇌ OH− + H₃O⁺

The water equilibrium constant (Kw) is the product of concentration

the ions:

Kw = [H₃O +] [OH-]

Kw value at 25° C = 10⁻¹⁴

It is known [H₃O +]=8.4 x 10⁻¹¹ M

then the concentration of [OH-] -hydroxide ion :

`\tt 10^(-14)=8.4* 10^(-11)* [OH^-]`

`\tt [OH^-]=(10^(-14))/(8.4* 10^(-11))=1.19* 10^(-4)\approx 1.2* 10^(-4)`