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Find the 22nd term of the arithmetic sequence whose common difference is d=4 and whose first term is a, = 3 PLEASE HELP! :(

1 Answer

4 votes

Answer:

22nd term is 81

Explanation:

In order to find the answer to this question you have to realize that the common difference is the rule the arithmetic sequence goes by, so all you have to do is add four to three, twenty two times or multiply the first term by


a =3


d=4


3+4=7+4=11+4=15+4=19+4=23+4=27+4=31+4=35+4=39+4=33+4=37+4=41+4=45+4=49+4=53+4=57+4=61+4=65+4=69+4=73+4=77+4=81


a=81

Hope this helps.

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User Daniel Omoto
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