Explanation:
Since we are not given the required parameters, we can use the following parameters
Given:
∠ A = 5 x + 30 °
∠ B = 2 x
Since △ABC is isosceles with AB = BC, then ∠ A = ∠ C (the base angles of an isosceles triangle are equal)
Since sum of angle in a triangle are the same, then;
∠ A + ∠ B + ∠ C = 180°
Substitute the given functions and get x;
5x+30 + 2x + 5x+30 = 180
12x + 60 = 180
12x = 180-60
12x = 120
x = 120/12
x = 10°
∠ A = 5x+30
∠ A = 5(10)+30
∠ A = 80°
Since ∠ A =∠ C
∠ C = 80°
For ∠ B;
∠ B = 2x
∠ B = 2(10)
∠ B = 20°
Let AB = 1, since AB = BC, BC = 1
To get AC, use the sin rule;
a/sin∠ A = b/sin∠ B
a/sin80 = 1/sin20
asin20 = sin80
a = sin80/sin20
a = 0.9848/0.3420
a = 2.879
Hence AC ≈ 3
Note that the values of the sides and angles are assumed.