Question

A sealed can of soda contain a pressure of 1.15 atm at 23°C. What is the new pressure at 79 °C? Report your answer to the hundredths place (two decimal places) You do NOT need units in your answer

Answer 1

P₂ = 1.37

Step-by-step explanation:

Given data:

Initial pressure = 1.15 atm

Initial temperature = 23°C (23+273= 296 K)

Final pressure = ?

Final temperature = 79°C (79+273=352 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1.15 atm / 296 K = P₂/352 K

P₂ = 1.15 atm × 352 K / 296 K

P₂ = 404.8 atm. K /296 K

P₂ = 1.37 atm