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A student collects 25 mL of gas at 96 kPa. What volume would this gas occupy at 101.325 kPa. There is no change in temperature or mass.

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6 votes

Answer:

The answer is 23.69 mL

Step-by-step explanation:

The new volume can be found by using the formula


P_1V_1 = P_2V_2

Since we are finding the new volume


V_2 = (P_1V_1)/(P_2) \\

From the question we have

101.325 kPa = 101325 Pa

96 kPa = 96000 Pa

From the question we have


V_2 = (25 * 96000)/(101325) = (2400000)/(101325) \\ = 23.68615840...

We have the final answer as

23.69 mL

Hope this helps you

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User Sakthisundar
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