Question

Plz Help...
Find x in the given triangle.

Answer 1

`\huge\boxed{x=2√(286)}`

Explanation:

Use the Pythagorean theorem:

`leg^2+leg^2=hypotenuse^2`

We have:

`leg=x\\leg=15\\hypotenuse=37`

Substitute and solve for x:

`x^2+15^2=37^2\\\\x^2+225=1269\qquad|\text{subtract 225 from both sides}\\\\x^2+225-225=1269-225\\\\x^2=1144\to x=√(1144)\\\\x=√(4\cdot286)\\\\x=\sqrt4\cdot√(286)\\\\x=2√(286)`