Answer:
20,000 bricks
Explanation:
length of brick(L)=22cm
breadth of brick(B)=15cm
now,
 area of brick(A)=L×B
 =22×15s.q.cm
 =0.033s.q.m
 again,
 length of court(l)=30m
 breadth of court(b)=22m
now,
 area of court(a)=l×b
 =30×22s.q.m
 =660s.q.m
lastly,
 no.of required brick=area of court/area of 
 brick
 =600 s.q.m/0.033s.q.m
 =20,000bricks