Question

5x^2-7x+1=0 solve please

Answer 1

`x=(7+√(29))/(10),\:x=(7-√(29))/(10)`

Explanation:

`5x^2-7x+1=0`

Solving with the quadratic formula:

`x_(1,\:2)=(-\left(-7\right)\pm √(\left(-7\right)^2-4\cdot \:5\cdot \:1))/(2\cdot \:5)`

`x_(1,\:2)=(-\left(-7\right)\pm √(29))/(2\cdot \:5)`

`x_1=(-\left(-7\right)+√(29))/(2\cdot \:5),\:x_2=(-\left(-7\right)-√(29))/(2\cdot \:5)`

`x=(7+√(29))/(10),\:x=(7-√(29))/(10)`

Answer 2

Look below

Explanation: