Can someone help me simplify the expression? Show your work :) ! Picture below !!!

asked Aug 21, 2021 62.5k views

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4 votes

Answer:

$$\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}$$

Explanation:

$\sqrt[3]{27x^6y^4}= \sqrt[3]{3^3x^6y^4}\\\sqrt[3]{27x^6y^4}=\sqrt[3]{3^3} \sqrt[3]{x^6} \sqrt[3]{y^4}$

therefore,

$\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}$

Nokuap answered Aug 27, 2021

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