Question

A six sided cube is rolled. What is the probability of getting a 3 and then a 4, givrn the first number rolled was 3.

Answer 1

1/6

Explanation:

Use conditional probability:

P(A given B) = P(A and B) / P(B)

P(4 given 3) = P(4 and 3) / P(3)

P(4 given 3) = (1/36) / (1/6)

P(4 given 3) = 1/6