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Given \sec A=\frac{14}{\sqrt{171}}secA= 171 ​ 14 ​ and that angle AA is in Quadrant I, find the exact value of \csc AcscA in simplest radical form using a rational denominator.

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User Naou
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Answer:

Explanation:


sec A=(14)/(√(171) ) \\cos ~A=(√(171) )/(14) \\sin ~A=√(1-cos^2A) =\sqrt{1-(171)/(196) } =\sqrt{(196-171)/(196) } =\sqrt{(25)/(96) } =\pm(5)/(14) \\csc A=\pm (14)/(5)

as A is in quadrant 1


so~csc~A=(14)/(5)

in quadrant 1 both sin A and csc A are positive.

answered
User Mukul Aggarwal
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