asked 73.5k views
3 votes
What is the volume of a sphere with a radius of 41.8 in, rounded to the

nearest tenth of a cubic inch?

asked
User Compski
by
7.6k points

2 Answers

7 votes

Answer:

305926.8

Explanation:

answered
User Rahul Gupta
by
7.6k points
2 votes

Answer:

305966.4in³

Explanation:

Given parameters:

Radius of the sphere = 41.8in

Unknown:

Volume of the sphere = ?

Solution:

The volume of sphere is expressed as:

V =
(4)/(3) \pi r^(3)

r is the radius;

Input the parameters and solve;

V =
(4)/(3 ) x
\pi x 41.8³

V = 305966.42in³

To nearest tenth of a cubic inch;

V = 305966.4in³

answered
User Oliver Lorton
by
7.8k points

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