Question

The pressure inside a sealed container of nitrous oxide (N,O) at the dentist's office is 8.5 kPa. If the

original temperature of 295 K is increased to 305 K, what will be the new pressure?

Answer 1

8.8kPa

Step-by-step explanation:

Given parameters:

Initial pressure = 8.5kPa

Initial temperature = 295k

New temperature = 305k

Unknown:

New pressure = ?

Solution:

To solve this problem, we have to apply the combined gas law when the volume is constant;

in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

`(P_(1) )/(T_(1) )` =
`(P_(2) )/(T_(2) )`

P and T are pressure and temperature

1 and 2 are initial and final states

Insert the parameters and solve;

`(8.5)/(295)` =
`(P_(2) )/(305)`

P₂ = 8.8kPa