Question

I need the answer asap plz!!

A sample of water vapor has a pressure of 36.0 Pa and a temperature of 300.0 K. If the pressure is
reduced to 32.0 Pa, what will the new temperature be?

Answer 1

266.7k

Step-by-step explanation:

Given parameters:

Initial pressure = 36Pa

Initial temperature = 300k

New pressure = 32Pa

Unknown:

New temperature = ?

Solution:

To solve this problem, we have to apply the combined gas law when the volume is constant;

in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

`(P_(1) )/(T_(1) )` =
`(P_(2) )/(T_(2) )`

P and T are pressure and temperature

1 and 2 are initial and final states

Insert the parameters and solve;

`(36)/(300)` =
`(32)/(T_(2) )`

T₂ = 266.7k