asked 133k views
1 vote
Cos2x + sin^2x =

A. 1 - sin^2x
B. 1
C. 3sin^2x - 1

2 Answers

4 votes


\cos(2x) + {sin}^(2)(x) =

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\cos(2x) = {cos}^(2)(x) - {sin}^(2)(x)

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{cos}^(2)(x) - {sin}^(2)(x) + {sin}^(2)(x) = \\


{cos}^(2)(x) = 1 - {sin}^(2)(x)

Thus the correct answer is (( A )) .

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answered
User Nathan Tuggy
by
8.8k points
5 votes

cos2x + sin^2x =1-2sin²x+sin²x=1-sin²x

so

your answer is:A. 1 - sin^2x

answered
User Vikram Tiwari
by
8.0k points

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