Question

What equation is graphed in this figure?

y−4=−13(x+2)


y−3=13(x+1)


y+2=−3(x−1)


y−5=3(x−1)

Number graph ranging from negative four to four on the x and y axes. A line is drawn on the graph that passes through begin ordered pair negative one comma four end ordered pair and begin ordered pair one comma negative two end ordered pair

Answer 1

C.
`y + 2 = -3(x - 1)`

Explanation:

All we need to create an equation of the given graph is a point on the line (x1, y1) and the slope (m) of the line.

Thus, equation of in point-slope form is given as
`y - y_1 = m(x - x_1)`.

Finding the slope (m) of the line of the graph given, using points (0, 1) and (1, -2).

`m = (y_2 - y_1)/(x_2 - x_1) = (-2 - 1)/(1 - 0) = (-3)/(1) = -3`

Substitute (x1, y1) = (1, -2) and m = -3 into
`y - y_1 = m(x - x_1)`

`y - (-2) = -3(x - 1)`

`y + 2 = -3(x - 1)`

The answer is C.