Answer:
The specific heat capacity of silver is 0.24 j/g.°C. 
Step-by-step explanation:
Given data: 
Mass of sample = 55.00 g
increase of temperature ΔT= 15.0 °C 
Heat absorbed = 193.9 J 
Specific heat capacity of silver = ? 
Solution: 
Specific heat capacity: 
It is the amount of heat required to raise the temperature of one gram of substance by one degree. 
Formula: 
Q = m.c. ΔT 
Q = amount of heat absorbed or released 
m = mass of given substance 
c = specific heat capacity of substance.
ΔT = change in temperature 
Now we will put the values in formula.
193.9 J = 55.00 g × c ×15.0 °C 
193.9 J = 825 g.°C × c 
c = 193.9 J / 825 g.°C 
c= 0.24 /g.°C 
The specific heat capacity of silver is 0.24 j/g.°C.