Question

Work out the equation of the line which has a gradient of 1/2 and passes through the point (2, -5)

Answer 1

y=½x-6

Explanation:

m= ½

equation of the line: y-y1=m(x-x1)

y+5=½(x-2)

y=½x-6

Answer 2

`y =(1)/(2)x-6`

Explanation:

Point-slope formula

`y-y_1=m(x-x_1)`

where:

• 
  `m` = slope (gradient)
• 
  `(x_1,y_1)` = point on the line

Given:

• Gradient (m) = ¹/₂
• Point = (2, -5)

Substitute the given values into the formula:

`\begin{aligned}y-y_1 & =m(x-x_1)\\\\\implies y-(-5) & =(1)/(2)(x-2)\\\\y+5 & =(1)/(2)x-1\\\\y & =(1)/(2)x-1-5\\\\y & =(1)/(2)x-6\end{aligned}`