Question

What is the rate of change of the line through (5,-11) and (2,-11)

Answer 1

Slope (m) =

ΔY

ΔX

= 0

θ =

arctan( ΔY )

ΔX

= 0°

ΔX = 2 – 5 = -3

ΔY = -11 – -11 = 0

Distance (d) = √ΔX2 + ΔY2 = √9 = 3

Equation of the line:

y = 0x – 11

When x=0, y = -11

Answer 2

0

Explanation:

rate of change for a line=its slope=(change in y)/(change in x)

=(-11-(-11)) / (-2-5)

= 0