asked 81.9k views
3 votes
Hi sorry I didn’t post the problem I’m having trouble with the first couple.

Hi sorry I didn’t post the problem I’m having trouble with the first couple.-example-1
asked
User Aloysius
by
8.5k points

1 Answer

4 votes

Answer:

Explanation:

#1


(5x^2-5x)/(x^2-2x+1)\\(5x(x-1))/((x-1)(x-1))\\ (5x)/(x-1)

#2

since it's negative, its npp (in the second part of the cubed factorization)


((x-2)(x^2+2x+4))/((x^2-4))\\((x-2)(x^2+2x+4))/((x-2)(x+2))\\ \\((x^2+2x+4))/((x+2))\\

answered
User PrimuS
by
7.8k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.