Given: 
• 3 + k , 18 - k and 5k + 1 are in AP . 
To find : 
• The value of K . 
Solution : 
• As we know that, In AP common difference is same : 
• b - a = c - b 
=> 2b = a + c 
Here , 
• a = 3 + k 
• b = 18 - k 
• c = 5k + 1 
=> 2 ( 18 - k ) = 3 + k + 5k + 1. 
=> 36 - 2k = 4 + 6k 
=> 36 - 4 = 6k + 2k 
=> 32 = 8k 
=> k = 32/8 
=> k = 4 
 Hence , the value of k is 4.