Question

There are 4 blue and 6 red marbles in a box. Two marbles are drawn at random without replacement. What is the probability having two blue marbles drawn?

Answer 1

Probability having two blue marbles(Without replacement) = 2/15

Explanation:

Given:

Number of blue marble = 4

Number of marble = 6

Find:

Probability having two blue marbles(Without replacement)

Computation:

Probability of first marble = 4 / 10

Probability of second marble = 3 / 9

Probability having two blue marbles(Without replacement) = [4/10][3/9]

Probability having two blue marbles(Without replacement) = 2/15