Answer:
Wonka bars=3 and Everlasting Gobstoppers=24
Explanation:
let the wonka bars be X
and everlasting gobstoppers be Y
the objective is to 
maximize 1.3x+3.2y=P
subject to constraints
 natural sugar 
4x+2y=60------1
 sucrose 
x+3y=75---------2
x>0, y>0
solving 1 and 2 simultaneously we have
4x+2y=60----1
x+3y=75------2
multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have
 4x+2y=60
 4x+12y=300
-0-10y=-240
10y=240
y=240/10
y=24
put y=24 in equation 2 we have'
x+3y=75
x+3(24)=75
x+72=75
x=75-72
x=3
put x=3 and y=24 in the objective function we have
maximize 1.3x+3.2y=P
1.3(3)+3.2(24)=P
3.9+76.8=P
80.7=P
P=$80.9