Work out the equation of the line which has a gradient of -2 and passes through the point (4, 8).

Question

asked Mar 21, 2023 55.4k views

1 Answer

Dave Long · Answer 1 · 2023-03-25T23:10:43+0000

Answer:

y = -2x + 16.

Explanation:

We are given the slope and a point on the line, so

we use the point-slope form of a straight line:

y - y1 = m(x - x1)

Here gradient m = -2, x1 = 4 and y1 = 8 , so we have:

y - 8 = -2(x - 4)

y - 8 = -2x + 8

y = -2x + 16.