Question

What is an equation that goes through (12, 5); m = -3
Please help

Answer 1

Explanation:

Use this formula:

y - y1 = m ( x - x1 )

We are told m = -3 and given the point (12 , 5) ---- > so x1 = 12 and y1= 5

Put these values into the formula above and you get:

y - y1 = m ( x - x1 )

y - 5 = -3 ( x - 12 )

y - 5 = -3x + 36

y = -3x + 36 + 5

y = -3x + 41