Question

A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?

Answer 1

`by \: Charles'\: law: \: \\ (v_(1))/(t_(1)) = (v_(2))/(t_(2)) \\`

Where v is the volume(in L) and t is the temperature(in °K)

`(8)/(250) = (v_(2))/(75) \\\\4/5 =v_2/3 \\\\\boxed{v_(2) = (12)/(5)}\\\\\\\huge{=2.5 l}`