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(1 point) . What is the equation, in standard form, of a parabola that models the values in the table? х -2 0 4 f(x) 0 -6 78 a.) y= 6x² + 5x - 4 b.) y=-4x2–5x + 6 c.) y=5x2 + 4x…

(1 point) . What is the equation, in standard form, of a parabola that models the values in the table? х -2 0 4 f(x) 0 -6 78 a.) y= 6x² + 5x - 4 b.) y=-4x2–5x + 6 c.) y=5x2 + 4x…
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(1 point) .

What is the equation, in standard form, of a parabola that models the values in the table?
х -2 0 4
f(x) 0 -6 78
a.) y= 6x² + 5x - 4
b.) y=-4x2–5x + 6
c.) y=5x2 + 4x = 6
d.) y=4x² + 5x- 6
please helpppp​

asked
User MSIslam
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8.6k points

1 Answer

2 votes

Answer:

Correct answer D. y = 4x2 + 5x – 6

Explanation:

just took the test

answered
User Susanna
by
7.5k points
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