Question

A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00-mL volumetric flask "B," which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask "A" is transferred by pipet to a 50.00-mL volumetric flask "B" and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask "B."

Answer 1

The answer is "0.015 M ".

Step-by-step explanation:

`M_1 = 1.25 \ M\\\\M_2 = M_2\\\\V_1 = 5.00 \ mL\\\\V_2 = 25.00 \ mL \\\\\bold{\text{Formula:}}\\\\\to M_1 * V_1 = M_2* V_2\\\\\to M_2 = ( M_1 * V_1)/(V_2)\\\\=(( 1.25 * 5.00 ))/( 25.00)\\\\=(( 6.25 ))/( 25.00)\\\\= 0.25 \ M \\\\`

If the volume
`V_2 = 3.00 \ mL`

`M_3=M_3 \\\\V_3 = 50.00 \ mL\\`

Formula:

`M_3 = (M_2 * V_2)/(V_3)`

`= ( 0.25 * 3.0)/(50.0)\\\\ = ( 0.75)/(50.0)\\\\ = 0.015 \ M \\\\`