Question

Please help urgent!!

Answer 1

The area of the rectangle is
`A=12b^6+6b^3-18b^2`

Explanation:

Area of a rectangle

A rectangle of height H and width W has an area of:

`A=H*W`

The rectangle shown in the figure has a height of:

`H=3b^2`

And a width of

`W=4b^4+2b-6`

The area is

`A=(3b^2)(4b^4+2b-6)`

Operating:

`A=(3b^2)*4b^4+(3b^2)*2b-(3b^2)6`

`A=12b^6+6b^3-18b^2`

The area of the rectangle is
`A=12b^6+6b^3-18b^2`