Question

The sum of three numbers is 123. The third number is 4 times the first. The second number is 9 more than the first. What are the numbers?

Answer 1

1st = 19

2nd = 76

3rd = 28

Explanation:

n + 4n + n + 9 = 123

6n + 9 = 123

6n = 114

n = 19

4(19) = 76

(19) + 9 = 28

Hope this helps :)