Question

Find the product of ( 2a2– 3b2) and ( a +b2- 3z)​

Answer 1

`2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z`

Explanation:

`(2a^2-3b^2)(a+b^2-3z)`

Start by distributing the
`2a^2` into all of the terms in between the second parentheses.

`2a^3+2a^2b^2-6a^2z`

Next, distribute the
`-3b^2` into all of the terms in between the second parentheses.

`-3ab^2-3b^4+9b^2z`

For the sake of simpler interpretation, I separated the two above, but they are together:

`2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z`

Since the terms are already in descending order, we do not need to rearrange them.