Question

What is the number of moles of glucose (C,H,O,) in 0.500
of a 0.40
M
solution?

Answer 1

Molarity (M) = Moles of Solute (mol) / Liters of Solution (L)

List Known Quantities into Above Equation

A. Molarity of Glucose Solution = 0.4 M

B. Liters of Glucose Solution = 0.5 L

Substitute Known Quantities into Above Equation

A. 0.4 M = x mol / 0.5 L

Solve for unknown value "x"

A. 0.5 * 0.4 = x

B. x = 0.2 mol of Glucose in the Solution