asked 175k views
5 votes
The speed of a car is increased at a constant rate. If the speed is increased by 54m/s over a 6 second period what is the acceleration

1 Answer

3 votes

Answer:

9ms^-2

Explanation:

a = dV/dt

a = 54ms^-1/6s

a = 9ms^-2

answered
User Marvin Saldinger
by
8.2k points
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