Question

If a+b+c=9 and ab+bc+ca=23 then a^3+b^3+c^3-3abc =?

Answer 1

Explanation:

a³ +b³ + c³ - 3abc =(a + b + c)(a² + b² + c² - [ab+bc+ac] )

= 9 (a² + b² + c²- 23)